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Coletta - Physics Fundamentals 1/e (Homework)

James Finch

Physics - College, section 1, Fall 2010

Instructor: Dr. Friendly

Current Score: 7/24

Due: Wednesday, August 25, 2010 20:00 EDT

About this Assignment

Question
Points
1 2 3 4 5 6 7 8 9
0/2 1 0/2 1/8 2 3 0/3 0/2 0/1
Total
7/24

Description

Here are some textbook questions from Physics Fundamentals 1/e by Vincent Coletta published by Physics Curriculum & Instruction, Inc.. Click here for a list of all of the questions coded in WebAssign.




1. 0/2 points All Submissions Notes Question: ColFunPhys1 4.P.006.
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1/5 1/5
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0/2
 
The particle shown below is at rest, where F1 = 5.85 N, and F2 = 10.1 N. Find the magnitude and direction of F.
magnitude
Enter a number.
Your answer is incorrect. N
direction
Enter a number.
Your answer is incorrect.° counterclockwise from the positive x-axis.



2. 1/1 points All Submissions Notes Question: ColFunPhys1 4.P.007.
Question part
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Submissions
1
1
1/5
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1/1
 
A boat is pulled at constant velocity by the two forces shown below, where F = 43.0 N, and θ = 11.0°. Find the horizontal force exerted on the boat by the water. The +x direction is to the right.
Enter a number.
Your answer is correct. N in the +x direction.


3. 0/2 points All Submissions Notes Question: ColFunPhys1 4.P.015.
Question part
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0/2
 
A 3.00 kg mass is acted upon by four forces in the horizontal (xy) plane, as shown in figure below, where F1 = 36.0 N, F2 = 48.0 N, F3 = 26.0 N, and F4 = 36.0 N. Find the acceleration of the mass.
magnitude
Enter a number.
Your answer is incorrect. m/s2
direction
Enter a number.
Your answer is incorrect.° above the positive x-axis.



4. 1/8 points All Submissions Notes Question: ColFunPhys1 4.WE.004.
Question part
Points
Submissions
1 2 3 4 5 6 7 8 9
0 0/1 0/1 0/1 1 0/1 0/1 0/1 0/1
1/5 0/5 0/5 1/5 1/5 1/5 0/5 0/5 0/5
Total
1/8
 
Example 4: Forces on a Man
Find the forces acting on a standing man whose mass is 104.0 kg.
Part 1 of 5 - Solution
According to Eq. 4-5, the man experiences a force w in the upwardYour answer is incorrect.

downward

 direction (the direction of g), and the magnitude of this force is
w = mg = (104.0 kg)((No Response)

9.80 m/s^2

 ) = (No Response)

1020 N
Part 2 of 5 - Solution
This force can also be expressed in pounds.
w = 1019.2 N 
1.00 lb
4.45 N
 = 23 lbsYour answer is incorrect.

229 lb
Part 3 of 5 - Solution
Since the man is standing at rest, his acceleration is zero and so the second law implies that there must be another force to cancel the weight and produce a resultant force equal to zero, as shown in the figure above. This other force is produced by the contact between his feet and the surface on which he is standing. We denote this surface force by S and use the second law to solve for it:
ΣF = ma = 0
S + F =
Enter an exact number.
Your answer is correct.
Thus
S =
Your answer is incorrect.



5. 2/2 points All Submissions Notes Question: ColFunPhys1 4.P.026.
Question part
Points
Submissions
1 2
1 1
1/5 1/5
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2/2
 
The block in the figure below rests on a frictionless surface. Find its instantaneous acceleration when the spring on the left is compressed 4.44 cm while the spring on the right is stretched 11.0 cm. Each spring has a force constant of 1.15 103 N/m.
magnitude
Enter a number.
Your answer is correct. m/s2
direction Your answer is correct.


6. 3/3 points All Submissions Notes Question: ColFunPhys1 4.P.029.
Question part
Points
Submissions
1 2 3
1 1 1
2/5 2/5 2/5
Total
3/3
 
Find the tension in each string in the figure below, where θ1 = 42.5°, θ2 = 22.0°, and w = 13.0 N.
T1 =
Enter a number.
Your answer is correct. N
T2 =
Enter a number.
Your answer is correct. N
T3 =
Enter a number.
Your answer is correct. N


7. –/3 points Notes Question: ColFunPhys1 4.P.031.
Question part
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1 2 3
0/1 0/1 0/1
0/5 0/5 0/5
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0/3
 
A crate weighing 5.20 102 N is lifted at a slow, constant speed by ropes attached to the crate at A and B in the figure below, where θ = 38.0°. These two ropes are joined together at point C, and a single vertical rope supports the system.
(a) Find the tension T1 in the vertical rope.
Enter a number.
 N

(b) Find the tensions T2 and T3 in the other ropes.
T2 =
Enter a number.
 N
T3 =
Enter a number.
 N


8. –/2 points Notes Question: ColFunPhys1 4.P.039.
Question part
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1 2
0/1 0/1
0/5 0/5
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0/2
 
Two blocks connected by a string are on a horizontal frictionless surface. The blocks are connected to a hanging weight by means of a string that passes over a pulley as shown in the figure below, where m1 = 2.20 kg, m2 = 3.25 kg, and m3 = 5.25 kg.
(a) Find the tension T in the string connecting the two blocks on the horizontal surface.
Enter a number.
 N

(b) How much time is required for the hanging weight to fall 10.0 cm if it starts from rest?
Enter a number.
 s


9. –/1 points Notes Question: ColFunPhys1 4.P.044.
Question part
Points
Submissions
1
0/1
0/5
Total
0/1
 
A car is stuck in a mudhole. In order to move the car, the driver attaches one end of a rope to the car and the other end to a tree 9.0 m away, stretching the rope as much as possible as shown in the figure below. The driver then applies a horizontal force of 4.50 102 N perpendicular to the rope at its midpoint. The rope stretches, with its center point moving 53.0 cm to the side as a result of the applied force. The car begins to move slowly. What is the tension in the rope?
Enter a number.
 N

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