Hoisting a Scaffold

Example 19 Hoisting a Scaffold

A window washer on a scaffold is hoisting the scaffold up the side of a building by pulling downward on a rope, as in Figure 4.36a. The magnitude of the pulling force is 540 N, and the combined mass of the worker and the scaffold is 155 kg. Find the upward acceleration of the unit.

Figure 4.36

(a)

A window washer pulls down on the rope to hoist the scaffold up the side of a building. The force results from the effort of the window washer and acts on him and the scaffold in three places, as discussed in Example 19.

(b)

The free-body diagram of the unit comprising the man and the scaffold.

Reasoning The worker and the scaffold form a single unit, on which the rope exerts a force in three places. The left end of the rope exerts an upward force

on the worker's hands. This force arises because he pulls downward with a 540-N force, and the rope exerts an oppositely directed force of equal magnitude on him, in accord with Newton's third law. Thus, the magnitude T of the upward force is T = 540 N and is the magnitude of the tension in the rope. If the masses of the rope and each pulley are negligible and if the pulleys are friction-free, the tension is transmitted undiminished along the rope. Then, a 540-N tension force

acts upward on the left side of the scaffold pulley (see part a of the drawing). A tension force is also applied to the point P, where the rope attaches to the roof. The roof pulls back on the rope in accord with the third law, and this pull leads to the 540-N tension force

that acts on the right side of the scaffold pulley. In addition to the three upward forces, the weight of the unit must be taken into account [W = mg = (155 kg)(9.80 m/s²) = 1520 N]. Part b of the drawing shows the free-body diagram.

Solution Newton's second law (ΣF_y = ma_y) can be applied to calculate the acceleration a_y: