Concepts & Calculations
Newton's three laws of motion provide the basis for understanding the effect of forces on the motion of an object, as we have seen. The second law is especially important, because it provides the quantitative relationship between net force and acceleration. The examples in this section serve as a review of the essential features of this relationship.
  Concepts & Calculations Example 20  Velocity, Acceleration, and Newton's Second Law of Motion
Figure 4.37 shows two forces, and , acting on a spacecraft; the plus signs indicate that the forces are directed along the +x axis. A third force also acts on the spacecraft but is not shown in the drawing. The craft is moving with a constant velocity of +850 m/s. Find the magnitude and direction of .
Figure zoom   Figure 4.37    Two horizontal forces, and , act on the spacecraft. A third force also acts but is not shown.
Concept Questions and Answers
 
Suppose the spacecraft were stationary. What would be the direction of ?
 
When the spacecraft is moving at a constant velocity of +850 m/s, what is the direction of ?

Solution   Since the velocity is constant, the acceleration is zero. The net force must also be zero, so that
Solving for F3 yields
The minus sign in the answer means that points opposite to the sum of and , or along the -x axis in Figure 4.37. The force has a magnitude of 8000 N, which is the magnitude of the sum of the forces and . The answer is independent of the velocity of the spacecraft, as long as that velocity remains constant.

  Concepts & Calculations Example 21  The Importance of Mass
On earth a block has a weight of 88 N. This block is sliding on a horizontal surface on the moon, where the acceleration due to gravity is 1.60 m/s2. As Figure 4.38a shows, the block is being pulled by a horizontal rope in which the tension is T = 24 N. The coefficient of kinetic friction between the block and the surface is μk = 0.20. Determine the acceleration of the block.
Figure zoom   Figure 4.38   

(a)  
A block is sliding on a horizontal surface on the moon. The tension in the rope is .
(b)  
The free-body diagram for the block, including a kinetic frictional force .


Concept Questions and Answers
 
Which of Newton's laws of motion provides a way to determine the acceleration of the block?
 
This problem deals with a situation on the moon, but the block's mass on the moon is not given. Instead, the block's earth-weight is given. Why can the earth-weight be used to obtain a value for the block's mass that applies on the moon?
 
Does the net force ΣFx equal the tension T?

Solution   Figure 4.38b shows the free-body diagram for the block. The net force along the x axis is ΣFx = +T - fk, where T is the magnitude of the tension in the rope and fk is the magnitude of the kinetic frictional force. According to Equation 4.8, fk is related to the magnitude FN of the normal force by fk = μkFN, where μk is the coefficient of kinetic friction. The acceleration ax of the block is given by Newton's second law as
We can obtain an expression for FN by noting that the block does not move in the y direction, so ay = 0 m/s2. Therefore, the net force ΣFy along the y direction must also be zero. An examination of the free-body diagram reveals that ΣFy = +FN - mgmoon = 0, so that FN = mgmoon. The acceleration in the x direction becomes
Using the earth-weight of the block to determine its mass, we find
The acceleration of the block is, then,





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